## Quiz 3 Submit on Moodle

### Quiz

Supppose the dominant allele "A" occurs 50% of the time. The recessive allele "a" must occur

- 0%
- 50%
- 25%
- 100%

Then, what is the probability of getting one dominant and one recessive gene, Aa?

- 0.1
- 0.9
- 0.9 x 0.1
- 2 x 0.9 x 0.1

If the gene frequencies are equal (0.5 A and 0.5 a) what are the probabilities for homozygous dominant, heterozygous and homozygous recessive?

- 33% AA, 33% Aa and 33% aa
- 50% AA, 25% Aa and 25% aa
- 50% AA, 0% Aa and 50% aa
- 25% AA, 50% Aa and 25% aa

Albinism occurs in every 1 in 10,000 people. What is p, the frequency of the recessive allele (a) for the disease?

- p = 0.0001
- p = 0.001
- p = 0.01
- p = 0.1

Assuming this value of p for albinism in a population, what is q (the frequency of the dominant allele, A)?

- 0.90
- 0.99
- 0.10
- 0.01

If p^{2} is the frequency of the disease (homozygous recessive), what is the meaning of q^{2}?

- The frequency of carriers who do not have the disease.
- The frequency of those heterozygous with respect to the disease.
- The frequency of homozygous recessive.
- The frequency of healthy non-carriers, (AA).

How do you calculate the numerical value of q^{2}?

- q
^{2} = (0.99)^{2} - q
^{2} = 2(0.99) - q
^{2} = 2(0.99 x 0.01) - q
^{2} = (0.01)^{2}

How is the numerical value of carriers calculated?

- 2pq
- pq
- p
^{2} + q^{2} - p
^{2} x q^{2}