- If ten bacterial cells double every 5 minutes, how many bacteria will there be in 30 minutes?
- 640
- 64
- 10
^{6} - 6.4 x 10
^{6}

- Fribbles reproduce every 6 hours in a litter of 10, then the parent dies.

If you start with 3 Fribbles, which equation would you use to calculate the population size after 5 days?- N
_{5 days}= 1 x 2^{20} - N
_{5 days}= 3 x 6^{20} - N
_{5 days}= 3 x 10^{20} - N
_{5 days}= 3 x 10^{5}

- N
- Suppose 10,000 tribbles eat poisoned grain, which kills half of them every hour. How many tribbles will be alive, three hours after eating the grain?
- 10
- 625
- 2500
- 1250

- Suppose a piece of meat contains 100,000 Salmonella bacteria. To meet safety standards, the food must be cooked for at least three half-lives after the point at which one bacterium would theoretically be left. If half of the bacteria die after one minute of cooking, what is the shortest time below that the food must be cooked?
- 5 minutes
- 10 minutes
- 20 minutes
- 40 minutes

- In a human population, if the dominant allele occurs 90% of the time, the recessive gene must occur
- 0%
- 10%
- 1%
- 90%

- If the frequency of a dominant allele, A, is 90% (or 0.9), the probability of getting two dominant alleles, AA, is
- 0.81
- 0.9
- 0.1
- .081

- If the gene frequencies are equal (0.5 A and 0.5 a) what are the probabilities for homozygous dominant, heterozygous and homozygous recessive?
- 33% AA, 33% Aa and 33% aa
- 50% AA, 25% Aa and 25% aa
- 50% AA, 0% Aa and 50% aa
- 25% AA, 50% Aa and 25% aa

- Albinism (with recessive inheritance) occurs in one out of 10,000 people. What is p, the frequency of the recessive allele (a) for the disease?
- p = 0.0001
- p = 0.001
- p = 0.01
- p = 0.1

- How is the fraction of carriers calculated?
- 2pq
- pq
- p
^{2}+ q^{2} - p
^{2}x q^{2}

- Suppose for a recessive trait the value of 2pq = 0.0198. Calculate the approximate number of carriers in a population of 10,000.
- 0.0198 x 10,000 = 198
- 1.98 x 10,000
- 0.0198/10,000
- 10,000 - 198