Quiz 3 Submit on Moodle
Quiz
Supppose the dominant allele "A" occurs 50% of the time. The recessive allele "a" must occur
- 0%
- 50%
- 25%
- 100%
Then, what is the probability of getting one dominant and one recessive gene, Aa?
- 0.1
- 0.9
- 0.9 x 0.1
- 2 x 0.9 x 0.1
If the gene frequencies are equal (0.5 A and 0.5 a) what are the probabilities for homozygous dominant, heterozygous and homozygous recessive?
- 33% AA, 33% Aa and 33% aa
- 50% AA, 25% Aa and 25% aa
- 50% AA, 0% Aa and 50% aa
- 25% AA, 50% Aa and 25% aa
Albinism occurs in every 1 in 10,000 people. What is p, the frequency of the recessive allele (a) for the disease?
- p = 0.0001
- p = 0.001
- p = 0.01
- p = 0.1
Assuming this value of p for albinism in a population, what is q (the frequency of the dominant allele, A)?
- 0.90
- 0.99
- 0.10
- 0.01
If p2 is the frequency of the disease (homozygous recessive), what is the meaning of q2?
- The frequency of carriers who do not have the disease.
- The frequency of those heterozygous with respect to the disease.
- The frequency of homozygous recessive.
- The frequency of healthy non-carriers, (AA).
How do you calculate the numerical value of q2?
- q2 = (0.99)2
- q2 = 2(0.99)
- q2 = 2(0.99 x 0.01)
- q2 = (0.01)2
How is the numerical value of carriers calculated?
- 2pq
- pq
- p2 + q2
- p2 x q2